Question

What are the mean and standard deviation of a binomial probability distribution with `n=12` and `p=31/32`?

Answer 1

Mean is `11.625` and Standard Deviation = `0.603`

Explanation:

The mean and standard deviation of a binomial probability distribution is given by `np` and `sqrt(npq)`, where `q-1-p`.

With `n=12` and `p=31/32`, `q=1-31/32` or `q=1/32`,

Mean = `12*31/32` = `11.625` and

Standard Deviation = `sqrt(12.(31/32)*(1/32)` = `(1/32)*sqrt372` = `19.2783/32` = `0.603`.