# What are the points of inflection, if any, of f(x)=2x^4-8x?

Apr 14, 2016

Since there is no change in concavity therefore there is no point of inflection

#### Explanation:

$f ' \left(x\right) = 8 {x}^{3} - 8$

$f ' ' \left(x\right) = 24 {x}^{2} = 0 \to x = 0$

$\left(- \infty , 0\right) \to +$ concave up

$\left(0 , + \infty\right) \to +$ concave up

Since there is no change in concavity therefore there is no point of inflection