What are the points of inflection of #f(x)=x^3 - 9x^2 + 8x #?

1 Answer
Jan 12, 2016

at #x=3#

Explanation:

Points of inflection occur when the second derivative of a function shifts sign (goes from positive to negative). This can also be viewed as a shift in concavity.

Find the second derivative:

#f(x)=x^3-9x^2+8x#
#f'(x)=3x^2-18x+8#
#f''(x)=6x-18#

The second derivative's sign could shift when it equals zero.

#f''(x)=0#
#6x-18=0#
#x=3#

There is a possible point of inflection when #x=3#.

We can check by analyzing the sign around the point #x=3#.

#(-oo,3)#

#f''(0)=-18larr"negative"#

#3#

#f''(3)=0larr"zero"#

#(3,+oo)#

#f''(4)=6larr"positive"#

As you can see, the concavity shifts from negative (concave down) to positive (concave up) when #x=3#. Thus, it is a point of inflection.

#f(x)# graphed:

graph{x^3-9x^2+8x [-3, 10, -78.3, 27.1]}