# What are the products of a reaction between zinc and silver chlorate?

Jan 22, 2017

$3 Z n + A g C l {O}_{3} + 6 H C l = 3 Z n C {l}_{2} + 3 {H}_{2} O + A g C l$

#### Explanation:

the reaction doesn't happen between solids but in solution, so you must write in ionic form.

Zn is a reductant and oxidizes to $Z {n}_{2} +$ while the clorate is an oxidant and reduces to $C {l}^{-}$.

The reactions are the following:
$Z n = 2 e + Z {n}^{2 +}$
$6 e + C l {O}_{3}^{-} + 6 {H}^{+} = 3 {H}_{2} O + C {l}^{-}$

Multiplying for three the first reaction and adding the two reaction you obtain:
$3 Z n + C l {O}_{3}^{-} + 6 {H}^{+} = 3 Z {n}^{2 +} + 3 {H}_{2} O + C {l}^{-}$

$A {g}^{+}$ is usefull only to salificate the anion:
$3 Z n + A g C l {O}_{3} + 6 {H}^{+} = 3 Z {n}^{2 +} + 3 {H}_{2} O + A g C l$

To produce the reaction is necessary a strong acid that gives the hydrogen ions, for example HCl, so the reaction may be written:
$3 Z n + A g C l {O}_{3} + 6 H C l = 3 Z n C {l}_{2} + 3 {H}_{2} O + A g C l$