What are the real or imaginary solutions of the polynomials $x^4-52x^2+576=0$ ?

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Answer 1 · 2017-01-14T09:55:50

$+-6 and +-4$ See the illustrative graph.

$f(x)=(x^2-26)^2-100$ . So,

(x^2-26)^2=100#, giving

$x^2=26+-10$

$=36 and 16$

$x=+-6 and +-4$

graph{x^4-52x^2+576 [-7, 7, -3.5, 3.5]}

What are the real or imaginary solutions of the polynomials x^4-52x^2+576=0x^4-52x^2+576=0?