Question

What are the rectangular coordinates of `(3, -π/3)`?

Answer 1

`x=3/2`
`y=(-3sqrt3)/2`

Explanation:

From the given: `r=3` and `theta=-pi/3`

`x=r*cos theta`
`x=3*cos (-pi/3)`
`x=3*(1/2)`
`x=3/2`

`y=r*sin theta`
`y=3*sin (-pi/3)`
`y=3*(-sqrt3)/2`

`y=(-3sqrt3)/2`

God bless...I hope the explanation is useful.