# What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2

##### 1 Answer

Jun 25, 2014

The reduced component is H₂.

We use oxidation numbers to identify oxidation and reduction products.

For this question, two rules are important:

- The oxidation number of an element is zero.
- The oxidation number of an ion is the same as its charge.

In the equation

Zn + 2H⁺ → Zn²⁺ + H₂

the oxidation numbers are

Zn = 0 (Rule 1)

H⁺ = +1 (Rule 2)

Zn²⁺ = +2 (Rule 2)

H₂ = 0 (Rule 1)

We see that the oxidation number of H has changed from +1 in H⁺ to 0 in H₂. This is a reduction of oxidation number.

**Reduction** is a **decrease in oxidation number**.

Thus, H⁺ has been reduced to H₂, and H₂ is the reduction product.

Hope this helps.