What are the six trig function values of #-pi/6#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer bp Dec 1, 2015 These are listed below. Explanation: #cos(-pi/6) = sqrt3 /2# #sin(-pi/6)= -1/2# #tan(-pi/6) = - 1/sqrt3# #sec (-pi/6)= 2/sqrt3# #cosec(-pi/6)= -2# #cot(-pi/6)= -sqrt3# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 3925 views around the world You can reuse this answer Creative Commons License