What are the solution in the interval [0, 2pie]? sec^2x-tan^2x=0

1 Answer
Apr 4, 2018

See explanation

Explanation:

We want to solve the equation

sec^2(x)-tan^2(x)=0

To get a better idea, write this in terms of sine and cosine

1/cos^2(x)-sin^2(x)/cos^2(x)=0

To simplify multiply both sides by cos^2(x)

1-sin^2(x)=0

Thus

sin^2(x)=1

=>sin(x)=+-sqrt(1)

=>sin(x)=+-1

Now i will leave it for you to find the solutions