# What are the solution in the interval [0, 2pie]? sec^2x-tan^2x=0

##### 1 Answer

Apr 4, 2018

See explanation

#### Explanation:

We want to solve the equation

#sec^2(x)-tan^2(x)=0#

To get a better idea, write this in terms of sine and cosine

#1/cos^2(x)-sin^2(x)/cos^2(x)=0#

To simplify multiply both sides by

#1-sin^2(x)=0#

Thus

#sin^2(x)=1#

#=>sin(x)=+-sqrt(1)#

#=>sin(x)=+-1#

Now i will leave it for you to find the solutions