What are the solution(s) of #2x^2 - 2x = 1#?
The approximate values are 1.37 and -0.37
Rewrite your original equation by moving the constant to the left side of the equation:
Here you have a typical
Use the ABC-formula to solve the equation.
Fill in 2 as a, -2 as b and -1 as c.
You can also use a quadratic equation calculator on line, for example: http://www.math.com/students/calculators/source/quadratic.htm