What are the solution(s) of #2x^2 - 2x = 1#?

1 Answer
Nov 6, 2015

Answer:

The approximate values are 1.37 and -0.37

Explanation:

Rewrite your original equation by moving the constant to the left side of the equation:
#2x^2 - 2x - 1 = 0#

Here you have a typical #ax^2 + bx + c = 0# equation.
Use the ABC-formula to solve the equation.

#(-b +- sqrt(b^2 - 4ac))/(2a)#

Fill in 2 as a, -2 as b and -1 as c.

You can also use a quadratic equation calculator on line, for example: http://www.math.com/students/calculators/source/quadratic.htm