# What are the values and types of the critical points, if any, of #f(x)=3e^(-2x^2))#?

##### 1 Answer

Jan 8, 2017

#### Explanation:

We can find critical points by equating the first derivative to zero:

So

We can now look at the sign of

#x < 0 => f'(x) > 0 #

#x > 0 => f'(x) < 0 #

So the point

graph{3e^(-2x^2) [-10, 10, -5, 5]}