What are the x-intercept(s) of #y =-x^2-2x+5#?

1 Answer
Alan P.
Oct 27, 2015

x-intercepts: #x=sqrt(6)-1# and #x=-sqrt(6)-1#

Explanation:

The x-intercepts are the values of #x# when #y=0# (the line of the graph crosses the X-axis when #y=0#)

#y=-x^2-2x+5=0#

#rArrx^2+2x-5 = 0#

Using the quadratic formula
#color(white)("XXX")x=(-2+-sqrt(2^2-4(1)(-5)))/(2(1))#

#color(white)("XXXX")= (-2+-sqrt(24))/2#

#color(white)("XXXX")=(-2+-2sqrt(6))/2#

#color(white)("XXXX")=-1+-sqrt(6)#

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