Question

What are the zero(s) of `f(x)=3x^2 +5 -9x`?

Answer 1

`x=(9+-sqrt(21))/6`

Explanation:

If `f(x)=3x^2+5-9x = 0`

`3x^2-9x+5 = 0`

Using the quadratic formula:
`color(white)("XXX")x = (9+-sqrt(9^2-4(3)(5)))/(2(3))`

`color(white)("XXX")x=(9+-sqrt(81-60))/6`

`color(white)("XXX")x=(9+-sqrt(21))/6`