# What are the zeros of the polynomial functionf(x)=(2x+1)(x-3)(x-2)?

Feb 9, 2016

$x = - \frac{1}{2} , x = 3 \mathmr{and} x = 2$

#### Explanation:

the zeros of a function are the particular values of x that make f(x) zero.

to find them we let f(x) = 0

here then : (2x+1)(x-3)(x-2) = 0

hence 2x+ 1 = 0 $\Rightarrow x = - \frac{1}{2}$

and x-3 = 0 $\Rightarrow x = 3$

and x-2 = 0 $\Rightarrow x = 2$