What are the zeros of the polynomial function#f(x)=(2x+1)(x-3)(x-2)#? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Jim G. Feb 9, 2016 Answer: # x =-1/2 , x = 3 and x = 2# Explanation: the zeros of a function are the particular values of x that make f(x) zero. to find them we let f(x) = 0 here then : (2x+1)(x-3)(x-2) = 0 hence 2x+ 1 = 0 # rArr x = -1/2 # and x-3 = 0 #rArr x = 3 # and x-2 = 0 # rArr x = 2 # Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 2764 views around the world You can reuse this answer Creative Commons License