What are the zeros of the polynomial functionf(x)=(x-3)(x-3)(x+5)?

Jun 26, 2018

$x = - 5 , x = 3 \text{ multiplicity 2}$

Explanation:

$\text{to obtain the zeros set } f \left(x\right) = 0$

${\left(x - 3\right)}^{2} \left(x + 5\right) = 0$

$\text{equate each factor to zero and solve for } x$

$x + 5 = 0 \Rightarrow x = - 5$

${\left(x - 3\right)}^{2} = 0 \Rightarrow x = 3 \text{ multiplicity 2}$