What are the zeros of the trinomial #4x^2-17x+4#?

1 Answer
Oct 30, 2017

Answer:

#x=1/4,x=4#

Explanation:

#"factorise the trinomial and equate to zero"#

#"the factors of + 16 which sum to - 17 are - 16 and - 1"#

#rArr4x^2-16x-x+4#

#=color(red)(4x)(x-4)color(red)(-1)(x-4)larrcolor(blue)"factor by grouping"#

#=(x-4)(color(red)(4x-1))#

#rArr(x-4)(4x-1)=0#

#"equate each factor to zero and solve for x"#

#x-4=0rArrx=4#

#4x-1=0rArrx=1/4#