# What charge would be needed on F2 to generate an ion with a bond order of 2?

Jun 12, 2018

You must generate a charge of +2.

#### Explanation:

Bond order in fluorine

Below is a molecular orbital diagram for a fluorine molecule.

The formula for bond order (BO) is

color(blue)(bar(ul(|color(white)(a/a)"BO" = "B-A"/2color(white)(a/a)|)))" "

where

$\text{B} =$ the number of bonding electrons
$\text{A} =$ the number of antibonding electrons

$\text{BO} = \frac{8 - 6}{2} = \frac{2}{2} = 1$

How do we change the bond order?

We change the number of electrons, but do we add or remove them?

The highest occupied molecular orbitals (HOMOs) are antibonding, and so is the lowest unoccupied molecular orbital (LUMO).

If we add electrons, they will go into the antibonding LUMO and decrease the bond order.

We must remove electrons from the antibonding HOMOs.

Each electron contributes 0.5 to the bond order, so we remove one electron each from the π"*"_(2p_text(x)) and π"*"_(2p_text(y)) orbitals.

The energy level diagram then looks like this.

$\text{BO} = \frac{8 - 4}{2} = \frac{4}{2} = 2$
We have removed two electrons, so the molecule becomes the ion $\text{F"_2^"2+}$ with a charge of +2.