What do you need to add to complete the square for #u^2+7u#?
1 Answer
May 19, 2015
For completing the square of a given equation, you have to add and subtract a term,and how to find that term ,i am gonna tell you...
- Firstly ,write the equation separately,
#u^2 + 7u # - Now,you have to do work upon the term which has less power,for ex in this case you have,7u
Now,divide this term by 2 and then square that term,for ex.
in this case divide 7u by 2 and then square it:
#7u# =>#7u/2# =>#(7u/2)^2# =>#49u^2/4# - now add and subtract this term to the initial equation,so that there is no effecyt to this equation,
#u^2 +7u+ 49u^2/4-49u^2/4# - now this equation forms of such a kind,
#(u^2 +7/2)^2 - 49u^2/4# - now this becomes a complete square.
Thank you.
