What do you need to add to complete the square for #u^2+7u#?

1 Answer
May 19, 2015

For completing the square of a given equation, you have to add and subtract a term,and how to find that term ,i am gonna tell you...

  • Firstly ,write the equation separately,
    #u^2 + 7u #
  • Now,you have to do work upon the term which has less power,for ex in this case you have,7u
    Now,divide this term by 2 and then square that term,for ex.
    in this case divide 7u by 2 and then square it:
    #7u# => #7u/2# => #(7u/2)^2# => #49u^2/4#
  • now add and subtract this term to the initial equation,so that there is no effecyt to this equation,
    #u^2 +7u+ 49u^2/4-49u^2/4#
  • now this equation forms of such a kind,
    #(u^2 +7/2)^2 - 49u^2/4#
  • now this becomes a complete square.
    Thank you.