What does it mean if a process is enthalpy-driven?

1 Answer
Jan 8, 2018

Consider,

$\Delta G = \Delta H - T \Delta S$

When $\Delta G < 0$, the process is energetically favorable.

When a system is enthalpy driven, generally $\Delta H < 0$ to compensate for $\Delta S < 0$. To be sure, it occurs spontaneously at lower temperatures, and nonspontaneously at higher temperatures.

Always think of that equation when considering these two variables!