Question

What does the graph of `(x-2)^2 + (y+6)^2=4` look like?

Answer 1

A circle.

Explanation:

Whenever you have an equation of the form `r = (x - h)^2 + (y - k)^2`, you have a circle with a radius of `sqrt(r)` and a centre at `(h, k)`.

Therefore, this circle will have a radius of `2" units"` and a centre at `(2, -6)`. We can now trace the following graph.

Hopefully this helps!