What fraction of the volume of an ice berg is visible above ocean water ? (density of ice =917) (density of water =1025)

1 Answer
Apr 17, 2018

0.105

Explanation:

According to Archimedes principle,

Weight of iceberg = Bouyant Force

"m"_i cancel"g" = "m"_w cancel"g"

Here

  • "m"_i = Mass of iceberg
  • "m"_w = Mass of water displaced

"V"_i "d"_i = "V"_w "d"_w color(white)(..)[∵ "Mass = Volume × Density"]

Volume of water displaced ("V"_w) = Volume of iceberg inside the water

or

Volume of water displaced ("V"_w) = Volume of iceberg ("V"_i) - Volume of iceberg visible ("V")

"V"_i "d"_i = ("V"_i - "V") "d"_w

"V"_i "d"_i = "V"_i "d"_w - "V" "d"_w

"V"/"V"_i = ("d"_w - "d"_i)/"d"_w = ("1025 kg/m"^3 - "917 kg/m"^3)/("1025 kg/m"^3) = color(blue)(0.105)