#bb r ( theta) = 5 e^ ( 2 theta) \ bb hat r#
Arc length:
#s = int_C dot s \ dt qquad = int_C sqrt(bb v * bb v ) \ dt qquad triangle#
#bb v ( theta) = d/(dt) (5 e^ ( 2 theta) \ bb hat r)#
Product rule:
#= 10 e^ ( 2 theta) dot theta \ bb hat r + 5 e^ ( 2 theta) d/(dt) (\ bb hat r) qquad square#
#d/(dt) (\ bb hat r)= d/(dt) ((cos theta),(sin theta)) #
#((- sin theta),(cos theta)) dot theta = bb hat theta dot theta#
So #square# is:
#bb v ( theta) = 10 e^ ( 2 theta) dot theta \ bb hat r + 5 e^ ( 2 theta) dot theta \ bb hat theta#
And #triangle# becomes:
#= int_C sqrt((10 e^ ( 2 theta) dot theta)^2 + (5 e^ ( 2 theta) dot theta \ )^2 ) \ dt#
#= int_C \ e^(2theta) sqrt( 10^2 + 5^2 ) qquad \ dot theta \ dt#
#=5sqrt(5) int_0^(2 pi) e ^(2 theta) qquad \ d theta#
#=(5sqrt(5))/2 ( e ^(4 pi ) - 1)#