# What is (1/2,4/5) in polar coordinates?

$r = \sqrt{{x}^{2} + {y}^{2}} = \sqrt{\frac{1}{4} + \frac{16}{25}} = 0.94$
$\theta = {\tan}^{-} 1 \left(\frac{y}{x}\right) = {\tan}^{-} 1 \left(\frac{\frac{4}{5}}{\frac{1}{2}}\right) = 1.01$
Use the formulas ${r}^{2} = {x}^{2} + {y}^{2} , \mathmr{and} \tan \theta = \frac{y}{x}$ to change from rectangular to polar.