What is #1\frac { 3 } { 4 } \div 7 \frac { 7 } { 8 }#?

2 Answers
Oct 12, 2016

#1 3/4-:7 7/8=2/9#

Explanation:

To divide by a fraction #a/b# is equivalent to multiplying by its reciprocal, which is #b/a#, obtained by just reversing numerator and denominator. If the divisor is a mixed fraction (as given in the question), we need to first convert it to improper fraction.

Hence #1 3/4-:7 7/8#

#hArr7/4-:63/8#

= #7/4xx8/63#

= #7/4xx(4xx2)/(7xx9)#

= #cancel7/cancel4xx(cancel4xx2)/(cancel7xx9)#

= #2/9#

Oct 16, 2016

Just an alternative way of solving this problem type

#2/9#

Explanation:

Write #1 3/4" as "7/4#

Write #7 7/8" as "63/8#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#7/4-:63/8#

Multiply by 1 and you do not change the value but 1 comes in many forms.

#[7/4color(magenta)(xx1)]-:63/8" "->" "[7/4color(magenta)(xx2/2)]-:63/8#

#14/8-:63/8" "=14-:63 =14/63#

#(14-:7)/(63-:7) = 2/9#