What is #[(7-5)^5 -: 8]-4#?

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Answer 1 · 2016-04-03T16:35:43

#0#

Solve the brackets first.

#7 - 5 = 2#

Now you have

#(2^5/8)-4#.

In fact, you don't even need to work out #2^5# if you know that #8 = 2^3#.

#2^5/2^3 = 2^(5-3) = 2^2 = 4#

And, obviously

#4 - 4 = 0#