What is #8sqrt48 - 6sqrt75 + 7sqrt80#?

1 Answer
Apr 15, 2016

#8sqrt48-6sqrt75+7sqrt80=2sqrt3+28sqrt5#

Explanation:

To simplify #8sqrt48-6sqrt75+7sqrt80#, let us first factorize numbers within square root sign i.e. #48#, #75# and #80#.

As #48=2xx2xx2xx2xx3#, #75=3xx5xx5# and #80=2xx2xx2xx2xx5#,

#8sqrt48-6sqrt75+7sqrt80 =#

#8sqrt(ul(2xx2xx2xx2)xx3)-6sqrt(3xxul(5xx5))+7sqrt(ul(2xx2xx2xx2)xx5)#

= #8xx2xx2xxsqrt3-6xx5xxsqrt3+7xx2xx2xxsqrt5#

= #32sqrt3-30sqrt3+28sqrt5#

= #2sqrt3+28sqrt5#