What is #a_9# for the geometric sequence #1/2, 1/4, 1/8, 1/16#?

1 Answer
Jun 11, 2016

The #"nth"# term of a geometric sequence is given by #t_n = a xx r^(n - 1)#

Explanation:

In this sequence, #a = 1/2#, #n = 9# and #r = ?#

The common ratio, abbreviated to #r#, can be found by using the formula #r = t_2/t_1#.

Calculating:

#r = t_2/t_1#

#r = (1/4)/(1/2)#

#r = 1/4 xx 2/1#

#r = 1/2#

Now, we know all the information we need to know to find #a_9#

#t_9 = 1/2 xx (1/2)^8#

#t_9 = 1/2 xx 1/256#

#t_9 = 1/512#

Therefore, the 9th term, or #a_9# is #1/512#.

Hopefully this helps!