Question

What is an equation of the line that passes through the points (-4, 3) and (-1, 6)?

Answer 1

Slope-intercept form: `y=x+7`
Point-slope form: `y-6=1(x+1) or y-3=1(x+4)`

Explanation:

To find the equation of the line, first, you must find the slope. Remember that the slope formula is

`m=(y_2-y_1)/(x_2-x_1)`

If you plug in the points (it does not matter which point is `(x_1,y_1)`,

`(6-3)/(-1+4)= 1`

Therefore, the slope is `1`.

Slope-intercept form:

`y=mx+b`

So

`3=1(-4) +b`

`b=7" "` (`b` is the same if you plug in `(-1,6)`)

So

`y=x+7`

Point-slope form:

`y-y_1=m(x-x_1)`

You can plug in one of the two points here.

`y-6=1(x+1)`

or

`y-3=1(x+4)`

Hope this helped.