# What is an example of a stoichiometry of reactions between ions in solutions practice problem?

Sep 24, 2015

Many example can be given for for stoichiometry reaction between
ions in solution

1. Reaction of strong acid with strong base. for example take 10 mL of 0.1 M HCl, ${H}_{2} S {O}_{4}$, $H N {O}_{3}$ titrate with 0.1 M sodium hydroxide. Calculate the volume of sodium hydroxide for neutralisation of acid with base.

HCl + NaOH = NaCl+ ${H}_{2} O$ Eq 1

One mole HCl = one mole NaOH

$H N {O}_{3} + N a O H = N a N {O}_{3} + {H}_{2} O$ Eq 2

one mole #HNO_3 = one mole

${H}_{2} S {O}_{4} + 2 N a O H = N {a}_{2} S {O}_{4} + 2 {H}_{2} O$Eq 3

One mole ${H}_{2} S {O}_{4}$ = 2 mole NaOH

For equation 1 & 2 10 mL of sodium hydroxide will be consumed, whereas for eq 3 20 mL of sodium hydroxide is consumed

1. Precipitation reaction

100 mL of 0.1 M $C a {\left(N {O}_{3}\right)}_{2} \mathmr{and} Z r {\left(N {O}_{3}\right)}_{4}$ present in separate reaction vessel are reacted with 0.1 M oxalic acid calculate the volume oxalic acid for precipitation of Ca and Zr as their oxalates

$C a {\left(N {O}_{3}\right)}_{2} + {H}_{2} {C}_{2} {O}_{4} = C a {C}_{2} {O}_{4} + 2 H N {O}_{3}$ Eq 4
$Z r {\left(N {O}_{3}\right)}_{4} + 2 {H}_{2} {C}_{2} {O}_{4} = Z r \left({C}_{2} {O}_{4}\right) 2 + 4 H N {O}_{3}$ Eq 5
Eq 4 One mole Ca = one mole Calcium oxalate
Eq 4 One mole Ca = one mole of Oxalic acid

Eq 5 One mole Zr = One mole Zr oxalate

Eq 5 One mole Zr = 2 mole oxalic acid

Therefore for Ca precipitation requires 100 mL, whereas for Zr it requires 200 mL
like this many example can be given for stoichiometry reactions