What is complex conjugate of #-a-b#?

1 Answer
May 16, 2016

Answer:

#-a-b#

Explanation:

Since every real number is a complex number with an imaginary part of #color(blue)0#, the given expression can be written as,

#-a-b+color(blue)0i#

To find the complex conjugate, negate the imaginary number, "#0i#," which becomes "#-0i#." Writing out the expression, the complex conjugate would be,

#-a-b-0i#

However,

#-a-b+0i=-a-b-0i#

Thus, the complex conjugate of "#-a-b#" is "#-a-b#" itself.