What is #f(x) = int -sinx dx# if #f(pi/3) = -6 #?
1 Answer
Oct 29, 2016
Explanation:
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(intsinx dx=-cosx)color(white)(2/2)|)))#
#rArrint-sinxdx=cosx+c# where c is the constant of integration.
We find c, using
#f(pi/3)=-6#
#rArrcos(pi/3)+c=-6#
#rArr1/2+c=-6rArrc=-13/2#
#rArrF(x)=cosx-13/2#