Evaluating the Constant of Integration
Key Questions
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If
G(x) is an antiderivative off(x) andG(x_0)=y_0 , thenG(x)=int f(x)dx=F(x)+C ,where
F(x) is any antiderivative off(x) .Since
G(x_0)=F(x_0)+C=y_0 ,we have
C=y_0-F(x_0) .
I hope that this was helpful.
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Normally, we want this integral function to be specified with a capital
f , so that we can specify the antiderivative asf(x) .However, using your variable naming, let's say that
F(x) is the antiderivative off'(x) , then by the Net Change Theorem, we have:f(x)=F(x)+C Therefore, the constant of integration is:
C=f(x)-F(x)
=f(2)-F(2)
=1-F(2) This is a simple answer, however for many students, it is very difficult to this this abstractly. So, let's look at a concrete example:
F(x)=x^3 to match your variables
F'(x)=f'(x)=3x^2 to match your variables
f(x)=int 3x^2 dx
=x^3+C
=F(x)+C Now, substitute the given values:
f(2)=x^3+C=1
2^3+C=1
F(2)+C=1
C=1-F(2) So, if an abstract problem makes it difficult for you to find a solution, start with a concrete one to help you find a pattern.
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If
F(x) is an antiderivative of a functionf(x) , that is,F'(x)=f(x) ,then
G(x)=F(x)+C , whereC is any constant,is also an antiderivative of
f(x) sinceG'(x)=[F(x)+C]'=F'(x)=f(x) .Hence, there are a family of functions (only differ by a constant) that are antiderivatives of
f(x) . In order to include all antiderivatives off(x) , the constant of integrationC is used for indefinite integrals.int f(x)dx=F(x)+C The importance of
C is that it allows us to express the general form of antiderivatives.
I hope that this was helpful.