Question

What is `lim_(x->-oo) x^2/(x^2-7)`?

Answer 1

`1`

Explanation:

We can divide both numerator and denominator by `x^2:`

`lim_(x->-oo)((cancel(x^2))/(cancel(x^2)))/(cancel(x^2)/cancel(x^2)-7/x^2)`

`=lim_(x->-oo)1/(1-7/x^2)=1/(1-7/(-oo)^2)=1`