What is ln(cos x )= 0 in [0,2pi)?
1 Answer
Mar 22, 2018
Explanation:
Given
#ln(cosx) = 0#
#cosx = e^0#
#cosx = 1#
#x = 0#
Hopefully this helps!
Given
#ln(cosx) = 0#
#cosx = e^0#
#cosx = 1#
#x = 0#
Hopefully this helps!