# What is my theoretical yield of sodium oxide if I start with 20 grams calcium oxide in the reaction 2NaCl + CaO -> CaCl_2 + Na_2O?

Feb 7, 2017

Approx. 20 g of $N {a}_{2} O$ could be isolated.

#### Explanation:

$2 N a C l + C a O \rightarrow C a C {l}_{2} + N {a}_{2} O$

$\text{Moles of calcium oxide}$ $=$ $\frac{20 \cdot g}{56.08 \cdot g \cdot m o {l}^{-} 1} = 0.357 \cdot m o l .$

Given the stoichiometric equation, which you have kindly provided, clearly, at most, I can get an equivalent quantity of $\text{natrium oxide}$.

And thus we multiply the molar quantity by the molar mass of natrium oxide to get:

0.357*molxx61.98*g*mol^-1=??g