Question

What is pH when `[H^+] = 8.43 * 10^-4` `M`?

Answer 1

`pH=3.07`

Explanation:

`pH=-log_10[H^+]`, equivalently `pH=-log_10[H_3O^+]`.

`-log_10(8.43xx10^-4)=-(-3.07)=3.07`