# What is the amount of energy needed to heat 55.0 g of water from 45°C to 67°C?

Apr 5, 2017

5.8 kJ

#### Explanation:

Use the equation,

$Q = m c \delta T$

where Q is heat flow (energy), m is mass, c is specific heat capcity and $\delta T$ is the change in tempreture ($T 2 - T 1$)

The specific heat capacity of water is $\left(4.816 \frac{J}{g \cdot C}\right)$

$Q = \left(55.0 g\right) \cdot \left(4.816 \frac{J}{g \cdot C}\right) \cdot \left(67 C - 45 C\right)$