What is the angular momentum of a rod with a mass of #15 kg# and length of #4 m# that is spinning around its center at #14 Hz#?

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Answer 1 · 2017-08-13T19:22:58

The angular momentum is #=1759.3kgm^2s^-1#

The angular momentum is #L=Iomega#

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

#=1/12*15*4^2= 20 kgm^2#

The angular velocity is

#omega=2pif=2pi*14=28pirads^-1#

So the angular momentum is

#L=20*(28pi) =1759.3kgm^2s^-1#