What is the angular momentum of a rod with a mass of 15 kg and length of 4 m that is spinning around its center at 14 Hz?

Aug 13, 2017

The angular momentum is $= 1759.3 k g {m}^{2} {s}^{-} 1$

Explanation:

The angular momentum is $L = I \omega$

where $I$ is the moment of inertia

The moment of inertia of a rod, rotating about the center is

$I = \frac{1}{12} \cdot m {L}^{2}$

$= \frac{1}{12} \cdot 15 \cdot {4}^{2} = 20 k g {m}^{2}$

The angular velocity is

$\omega = 2 \pi f = 2 \pi \cdot 14 = 28 \pi r a {\mathrm{ds}}^{-} 1$

So the angular momentum is

$L = 20 \cdot \left(28 \pi\right) = 1759.3 k g {m}^{2} {s}^{-} 1$