What is the angular momentum of a rod with a mass of $15 kg$ and length of $4 m$ that is spinning around its center at $14 Hz$ ?

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Answer 1 · 2017-08-13T19:22:58

The angular momentum is $=1759.3kgm^2s^-1$

The angular momentum is $L=Iomega$

The moment of inertia of a rod, rotating about the center is

$I=1/12*mL^2$

$=1/12*15*4^2= 20 kgm^2$

The angular velocity is

$omega=2pif=2pi*14=28pirads^-1$

So the angular momentum is

$L=20*(28pi) =1759.3kgm^2s^-1$

What is the angular momentum of a rod with a mass of 15 kg15 kg and length of 4 m4 m that is spinning around its center at 14 Hz14 Hz?