What is the angular momentum of a rod with a mass of $4 k g$ $4 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $2 H z$ $2 Hz$ ?

Question

1388 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-09T11:05:41

The angular momentum is $= 150.8 k g m^{2} s^{- 1}$ $=150.8kgm^2s^-1$

The angular momentum is $L = I ω$ $L=Iomega$

where $I$ $I$ is the moment of inertia

and $ω$ $omega$ is the angular velocity

The moment of inertia of a rod, rotating about the center is

$I = \frac{1}{12} \cdot m L^{2}$ $I=1/12*mL^2$

$= \frac{1}{12} \cdot 4 \cdot 6^{2} = 12 k g m^{2}$ $=1/12*4*6^2= 12 kgm^2$

The angular velocity is

$ω = 2 \cdot 2 π$ $omega=2*2pi$

$= (4 π) r a d s^{- 1}$ $=(4pi) rads^(-1)$

The angular momentum is

$L = 12 \cdot 4 π = 48 π = 150.8 k g m^{2} s^{- 1}$ $L=12*4pi=48pi=150.8kgm^2s^-1$

What is the angular momentum of a rod with a mass of 4 kg4kg4 kg and length of 6 m6m6 m that is spinning around its center at 2 Hz2Hz2 Hz?