What is the answer to cos (3pi/8)? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. Apr 5, 2016 #- (sqrt(2 - sqrt2)/2)# Explanation: Call #cos ((3pi)/8) = cos t# --> #cos 2t = cos ((3pi)/4) = -sqrt2/2# Apply the identity; #cos 2t = 2cos^2 t - 1 = - sqrt2/2# #2cos^2 t = 1 - sqrt2/2 = (2 - sqrt2)/2# #cos^2 t = (2 - sqrt2)/4# #cos t = - (sqrt(2 - sqrt2))/2# --> since cos ((3pi)/4) is negative Answer: #cos t = cos ((3pi)/4) = - (sqrt(2 - sqrt2))/2# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 4157 views around the world You can reuse this answer Creative Commons License