What is the antiderivative of #sec^2(x)#? Calculus Introduction to Integration Integrals of Trigonometric Functions 1 Answer Jim H Jan 25, 2016 #tanx +C# Explanation: #d/dx(tanx) =sec^2x#, so #tanx# in an antiderivative of #sec^2x# and the general antiderivative of #sec^2x# is #tanx+C#. Answer link Related questions How do I evaluate the indefinite integral #intsin^3(x)*cos^2(x)dx# ? How do I evaluate the indefinite integral #intsin^6(x)*cos^3(x)dx# ? How do I evaluate the indefinite integral #intcos^5(x)dx# ? How do I evaluate the indefinite integral #intsin^2(2t)dt# ? How do I evaluate the indefinite integral #int(1+cos(x))^2dx# ? How do I evaluate the indefinite integral #intsec^2(x)*tan(x)dx# ? How do I evaluate the indefinite integral #intcot^5(x)*sin^4(x)dx# ? How do I evaluate the indefinite integral #inttan^2(x)dx# ? How do I evaluate the indefinite integral #int(tan^2(x)+tan^4(x))^2dx# ? How do I evaluate the indefinite integral #intx*sin(x)*tan(x)dx# ? See all questions in Integrals of Trigonometric Functions Impact of this question 92576 views around the world You can reuse this answer Creative Commons License