What is the antiderivative of #sinx^3#?
1 Answer
Jun 13, 2017
If you mean
Explanation:
Here is one possibility
# = int ((1-cos^2 x) sinx dx #
# = int sinx dx + int underbrace(cos^2x)_u underbrace((-sinx) dx)_(du)#
# = -cosx + cos^3x/3 +C#
As is typical of expressions involving trigonometric functions, there are other ways to express this family of functions.
(WolframAlpha gives