What is the antiderivative of #sinx^3#?

1 Answer
Jun 13, 2017

If you mean #(sinx)^3#, please see below. If you mean #sin(x^3)#, I can't help.

Explanation:

Here is one possibility

#int (sinx)^3 dx = int sin^2x sinx dx#

# = int ((1-cos^2 x) sinx dx #

# = int sinx dx + int underbrace(cos^2x)_u underbrace((-sinx) dx)_(du)#

# = -cosx + cos^3x/3 +C#

As is typical of expressions involving trigonometric functions, there are other ways to express this family of functions.

(WolframAlpha gives #1/12(cos(3x)-9cosx)+C# and simplifies the difference between our basic answers to #0#.)