Question

What is the antiderivative of `sqrt(sinx)`?

Answer 1

This is an advanced kind of antiderivative.

Explanation:

According to WolframAlpha, it is `-2E(1/4(pi - 2x)|2) +C`. Where `E(x|m)` is the elliptic integral of the second kind with parameter `m = k^2`.

No. I can't explain that.