What is the approximate distance between points (-7,2) and (11, -5)?

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Answer 1 · 2016-10-24T15:51:12

Distance between #(-7,2)# and #(11,-5)# is approximately #19.3#.

The distance between two points #(x_1,y_1)# and #(x_2,y_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

Hence, distance between #(-7,2)# and #(11,-5)# is

#sqrt((11-(-7))^2+((-5)-2)^2)#

= #sqrt((11+7)^2+(-5-2)^2)#

= #sqrt(18^2+(-7)^2)#

= #sqrt(324+49)#

= #sqrt373#

= #19.3132# or say #19.3#