What is the approximate mass of one water molecule?

1 Answer
Oct 29, 2015

You can determine that by using the molar mass in "g/mol" of the water molecule and converting so that you get the absolute mass in "g".

The molar mass is "MM"_("H"_2"O")" = 18.015 g/mol".

If you don't remember that, you can also look it up on Wikipedia, or refer to a periodic table and add up the molar masses of two hydrogen atoms and one oxygen atom.

"MM"_("H"_2"O") = 2*"1.0079 g/mol H" + "15.999 g/mol O"

= "18.015 g/mol H"_2"O"

Now we just need the relationship between the units "mol" and "number of things in a mol".

You may have been taught Avogadro's number, which is 6.0221413xx10^(23) "things/mol", and you can use that for the stoichiometric conversion. You multiply by the reciprocal to cancel out the units because the goal for the final units is "absolute mass"/("molecule H"_2"O").

("18.015 g H"_2"O")/cancel("mol H"_2"O") xx cancel("1 mol H"_2"O")/(6.0221413xx10^(23) "molecules of H"_2"O")

= color(blue)(2.9915xx10^(-23) "g/molecule H"_2"O")