What is the arclength of #(t-1,t/(t+5))# on #t in [-1,1]#?
1 Answer
Apr 20, 2018
The arc length is approximately
Explanation:
The arc length of parametric functions is
#int_(-1)^1 sqrt((dy/(dt))^2 + ((dx)/(dt))^2) dt#
#int_(-1)^1 sqrt(1 + ((t + 5 - t)/(t + 5)^2)^2) dt#
#int_(-1)^1 sqrt(1 + 25/(t + 5)^4) dt#
Use a calculator to evaluate this tricky integral. Thus
#I = 2.05#
Hopefully this helps!
