What is the arclength of the polar curve f(theta) = 2thetasin(5theta)-thetacot2theta f(θ)=2θsin(5θ)−θcot2θ over theta in [pi/12,pi/3] θ∈[π12,π3]?
1 Answer
Jun 3, 2018
Explanation:
From
we get by differentiating with respect to
and our integral is given by