# What is the arclength of the polar curve #f(theta) = 4sin(2theta)-2sec^2theta # over #theta in [0,pi/8] #?

##### 1 Answer

May 2, 2017

#### Answer:

#### Explanation:

Arclength on the polar plane has the following formula:

Given the equation

Plug in the expressions for

Use a graphing calculator to evaluate: