# What is the arclength of the polar curve #f(theta) = sin4theta-cos3theta # over #theta in [pi/3,pi/2] #?

##### 1 Answer

Mar 20, 2017

#### Answer:

The arclength is approximately

#### Explanation:

The equation for arclength of a polar curve is:

In this case,

So, the arclength can be found by:

*Final Answer*

I am not entirely sure how to solve this integral manually; if anyone else has a valid method of integration, feel free to extend this answer, but as far as I can see, the only way to solve this problem is with a graphing calculator or similar interface.